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In the app's font they look alike, and run 38729120356 read the descriptions "CI seed group" and "CI seed channel" as "Cl seed ...", failing four checks.
147 lines
5.8 KiB
Python
Executable File
147 lines
5.8 KiB
Python
Executable File
#!/usr/bin/env python3
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# Reads the words tesseract found on a screenshot and prints the phrases on screen, or where one text is.
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#
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# screen-text.py <scale> <ocr dir> lines one phrase per line: centre x,y and its words
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# screen-text.py <scale> <ocr dir> find <text> "x y left top right bottom": centre and box of the text, from the phrase
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# that is exactly the text, else the first one containing it; fails if none does
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#
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# <ocr dir> has tesseract's TSV of the dark-text and the light-text pass (dark.tsv, light.tsv), in pixels of the
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# screenshot enlarged by <scale>, and gray.pgm, the screenshot in 8-bit grayscale. Printed coordinates are
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# screen pixels. Text is compared ignoring case, spaces and punctuation.
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import csv
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import os
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import re
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import statistics
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import sys
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# Luminance (0-255) below which a background is dark enough for light text: blue buttons are about 115, disabled grey
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# ones about 137, light ones (window, fields, cards) over 230.
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LIGHT_BACKGROUND = 190
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# In the app's font a capital I looks like a lowercase l, and OCR reads it as one, so the two compare equal.
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def key(text):
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return re.sub(r"[^0-9a-z]", "", text.lower()).replace("l", "i")
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def read_words(path, scale):
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words = []
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with open(path, newline="") as f:
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for row in csv.DictReader(f, delimiter="\t", quoting=csv.QUOTE_NONE):
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text = (row["text"] or "").strip()
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if row["level"] != "5" or not key(text):
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continue
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left, top, width, height = (int(row[k]) / scale for k in ("left", "top", "width", "height"))
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words.append({"text": text, "key": key(text), "l": left, "t": top, "r": left + width, "b": top + height})
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return words
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def read_gray(path):
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with open(path, "rb") as f:
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data = f.read()
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header = re.match(rb"P5\s+(\d+)\s+(\d+)\s+(\d+)\s", data)
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if int(header[3]) != 255:
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sys.exit(f"{path}: expected 8-bit samples, got maximum {int(header[3])}")
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return int(header[1]), int(header[2]), data[header.end():]
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# The median of the rows 2 to 4 pixels above and below the word: its background, free of its own letters.
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def background(gray, w):
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width, height, luminance = gray
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left, right = max(int(w["l"]), 0), min(int(w["r"]), width - 1)
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rows = [int(w["t"]) - d for d in (2, 3, 4)] + [int(w["b"]) + d for d in (2, 3, 4)]
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return statistics.median(luminance[y * width + x] for y in rows if 0 <= y < height for x in range(left, right + 1))
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def box(words):
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return min(w["l"] for w in words), min(w["t"] for w in words), max(w["r"] for w in words), max(w["b"] for w in words)
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def centre(words):
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left, top, right, bottom = box(words)
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return (left + right) / 2, (top + bottom) / 2
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# Each pass also reads noise where its polarity doesn't apply (the gaps between dark letters look like light text),
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# so a word counts only from the pass that matches the background under it.
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def screen_words(ocr_dir, scale):
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gray = read_gray(os.path.join(ocr_dir, "gray.pgm"))
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def on_light_background(w):
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return background(gray, w) >= LIGHT_BACKGROUND
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dark = read_words(os.path.join(ocr_dir, "dark.tsv"), scale)
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light = read_words(os.path.join(ocr_dir, "light.tsv"), scale)
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return [w for w in dark if on_light_background(w)] + [w for w in light if not on_light_background(w)]
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# A word continues a phrase when it is on the same line as the phrase's last word and at most 1.5 of their height after it;
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# wider gaps separate UI elements.
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def follows(a, b):
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h = min(a["b"] - a["t"], b["b"] - b["t"])
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return min(a["b"], b["b"]) - max(a["t"], b["t"]) >= 0.5 * h and -0.5 * h <= b["l"] - a["r"] <= 1.5 * h
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def phrases(words):
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result = []
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for w in sorted(words, key=lambda w: w["l"]):
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phrase = next((p for p in result if follows(p[-1], w)), None)
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if phrase:
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phrase.append(w)
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else:
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result.append([w])
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return sorted(result, key=lambda p: (min(w["t"] for w in p), p[0]["l"]))
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# OCR can split or join words ("#ci_group" read as "#ci_ group"), so words are compared by their joined characters.
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# It can also glue an icon to the first word, or punctuation or the text cursor to the last, so the text may start
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# inside the first word and end inside the last when at least 4 of its characters are in that word.
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def span_matches(words, target):
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keys = [w["key"] for w in words]
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joined = "".join(keys)
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start = joined.find(target)
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while start >= 0:
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end = start + len(target)
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first_ok = start == 0 or len(keys[0]) - start >= 4
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last_ok = end == len(joined) or len(keys[-1]) - (len(joined) - end) >= 4
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if start < len(keys[0]) and end > len(joined) - len(keys[-1]) and first_ok and last_ok:
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return True
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start = joined.find(target, start + 1)
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return False
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def find(all_phrases, text):
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target = key(text)
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if not target:
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return None
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for phrase in all_phrases:
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if "".join(w["key"] for w in phrase) == target:
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return phrase
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for phrase in all_phrases:
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for i in range(len(phrase)):
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for j in range(i + 1, len(phrase) + 1):
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if span_matches(phrase[i:j], target):
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return phrase[i:j]
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return None
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def main():
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scale, ocr_dir, command, args = float(sys.argv[1]), sys.argv[2], sys.argv[3], sys.argv[4:]
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on_screen = phrases(screen_words(ocr_dir, scale))
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if command == "lines":
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for phrase in on_screen:
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x, y = centre(phrase)
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print(f"{round(x)},{round(y)} {' '.join(w['text'] for w in phrase)}")
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elif command == "find":
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words = find(on_screen, args[0])
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if not words:
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sys.exit(1)
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print(" ".join(str(round(v)) for v in centre(words) + box(words)))
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else:
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sys.exit(f"unknown command: {command}")
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main()
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